In a room of 57 or more people, the probability of two people having the same birthday is 99%.
In a group of 23 randomly chosen people, that probability is 50%. For a full explanation, see Birthday Paradox [wiki]
In a room of 57 or more people, the probability of two people having the same birthday is 99%.
In a group of 23 randomly chosen people, that probability is 50%. For a full explanation, see Birthday Paradox [wiki]
Say there are 4 students in the class, what is the probability that 2 or more student has the same birthday? I would like to know how to so solve this WITHOUT using the inversion technique[1 - {364/365 * 363/365 * 362/365}]. I believe it involve some
Your government schools at work.
How long until someone who can do simple math without a calculator is burned at the stake for witchcraft?